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Current-voltage characteristics

Plot current against potential difference for a component and the shape of the graph identifies it. Three characteristics are required: a resistor at constant temperature, a filament lamp and a diode. Only the first obeys Ohm's law.

Builds on Current, charge and the direction problem.

IN THIS TOPIC

  • Sketch and interpret the I-V characteristics of an ohmic conductor, a filament lamp and a semiconductor diode, explaining the shape of each.
  • Quote Ohm's law as the special case I ∝ V under constant physical conditions, and read resistance off any characteristic as V/I at a point.

COMMON MISCONCEPTION

Ohm's law applies to everything.

Taking a component's portrait

The circuit is simple enough. Vary the pd across the component, record the current through it, plot one against the other. Unless a question says otherwise the meters are ideal, meaning zero resistance in the ammeter and infinite resistance in the voltmeter, so neither disturbs what it is there to measure.

There is a small trap in the plotting itself. Exam papers put either quantity on the horizontal axis, and the same component's curve looks reflected when the axes swap. Read the axis labels before you read the shape.

The ohmic conductor

A metal wire held at constant temperature gives the simplest characteristic of all, a straight line through the origin.

An ohmic conductor: current proportional to pd, a straight line through the originVII ∝ Vsame gradient everywhere
FIG. 1The ohmic conductor's characteristic: a straight line through the origin, the same in both directions.

That straight line is Ohm's law. Current is proportional to pd, I ∝ V, provided physical conditions stay constant, and the proviso carries the law's whole content. Treat the law as the name for one well-behaved special case, the case where V/I happens to stay fixed. Plenty of components ignore it, and the next two break it openly.

The filament lamp

A lamp's filament runs white-hot, and the current itself does the heating. More current means a hotter filament, whose metal ions vibrate more violently, obstructing the charge carriers more often, so the resistance rises with the current.

A filament lamp: the curve flattens because the filament heats and its resistance risesVIflattens: resistance rising
FIG. 2The filament lamp's characteristic: steep near the origin, flattening as the filament heats and its resistance climbs.

The graph shows exactly that. Steep near the origin, where the filament is coolest, then flattening as V grows and the heating bites. Symmetry through the origin comes for free, since the filament behaves the same way whichever way the current runs.

The diode

A semiconductor diode is a one-way valve. In reverse, and in forward bias below a threshold pd of about 0.6 V, it passes almost no current; beyond the threshold the current climbs very steeply for tiny increases in pd. The arrow in the circuit symbol points the way conventional current is allowed through, and getting that arrow round the wrong way is what invalidates a sketched circuit.

A semiconductor diode: almost no current until the threshold, then a steep rise; almost none in reverseVIthreshold, about 0.6 Vreverse: almost nothing
FIG. 3The diode's characteristic: negligible reverse current before breakdown, nothing much below the forward threshold, then a near-vertical rise.

Reading resistance from the graph

At any point on any characteristic the definition still applies. R = V/I, the ratio of the two coordinates at that point. Along the ohmic line that ratio comes out the same everywhere, which is what ohmic means. Along the lamp's curve it grows as you move outwards.

Now the error that costs more marks than any other in this unit. On a curve, the gradient of the tangent and the ratio V/I are two different numbers, and only the ratio gives the resistance. The tangent slope has a genuine meaning of its own, but write it down as the resistance and the mark is gone. Coordinates, every time.

WORKED EXAMPLE

A diode, above and below its knee

From a diode's characteristic: at 0.65 V the current is 20 mA; at 0.40 V it is too small to read. Find the resistance at each point.

At 0.65 V the ratio gives R = V/I = 0.65/0.020 = 33 Ω, a diode conducting freely past its threshold.

At 0.40 V the current is effectively zero, so V/I is enormous. Below the threshold a diode is an open switch for all practical purposes.

One component, two utterly different resistances, both read as the ratio of coordinates. A single quoted resistance for a diode is a meaningless number, and saying so is often the mark.

GUIDED PRACTICE

Predict the hot wire's portrait

A metal wire's I-V characteristic is drawn cold. Predict, with a reason, how the graph changes if the whole experiment is repeated with the wire held at a higher steady temperature.

Show the working

Hotter metal vibrates more violently, so the electrons scatter more often and the resistance rises.

Higher resistance draws a shallower straight line, less current at every voltage. It stays straight because the temperature is being held fixed. A filament lamp curves only because it heats itself as you push it.

ASSESSMENT FOCUS

  • Resistance from a characteristic is the ratio V/I at the point, never the tangent's gradient. On a curve the two differ, and the mark scheme distinguishes them.
  • The lamp explanation is a chain and the order is marked. Current heats the filament, the ions vibrate with larger amplitude, the charge carriers collide with them more often, the resistance rises. Every link scores.
  • Quote Ohm's law with its condition attached, I ∝ V provided physical conditions, principally temperature, remain constant. Drop the condition and you drop the mark.
  • Check which axis is which before describing any shape. Put V up the vertical axis and every curve reflects, so the diode's steep rise becomes a flat run.

CHECK YOURSELF

From a filament lamp's characteristic: at 2.0 V the current is 0.50 A, and at 12 V it is 1.5 A. Find the resistance at each point, and explain the change.

Show a hint

Resistance is a ratio of coordinates, taken twice.

Show the answer

At 2.0 V, R = V/I = 2.0 / 0.50 = 4.0 Ω. At 12 V, R = 12 / 1.5 = 8.0 Ω.

Resistance has doubled because the larger current runs the filament far hotter. Its ions vibrate harder, the carriers collide with them more often, and each volt now drives proportionally less current.

R is the ratio V over I at a point, never the gradient of a curve.

WORKBOOK

Printable practice for this topic: original exam-style questions with room to work, and a fully worked answer book. Free to use; please do not redistribute or sell.

19 questions on this topicAnswer them one at a time and mark yourself against the mark scheme.Practise this topic

Or read them with their mark schemes on the current-voltage characteristics questions page.

7 flashcards on this topicDefinitions, off-sheet equations and a spot-the-error card, scheduled by spaced repetition in your browser.Revise with flashcards

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  • Sketch and interpret the I-V characteristics of an ohmic conductor, a filament lamp and a semiconductor diode, explaining the shape of each.
  • Quote Ohm's law as the special case I ∝ V under constant physical conditions, and read resistance off any characteristic as V/I at a point.

Open the full revision checklist to track your progress across the whole unit.