Physics › Particles › Energy, momentum and particle tracks
Energy, momentum and particle tracks
A process can pass every quantum-number check and still be forbidden, because energy and momentum must also be conserved. The free proton is the standard example. You will also learn to read these two checks off a detector photograph. The curl of a track gives the sign of the charge, and the radius gives the momentum through r = p/BQ. A tightening spiral shows energy being lost.
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Conservation laws, part 2 of 2. Part 1 is The conserved quantities.
Builds on Force on a moving charge.
IN THIS TOPIC
- Recognise that energy and momentum are conserved in every interaction, and that either can forbid one.
- For Edexcel, interpret a particle-track photograph, reading the sign of a charge from the curl, the momentum from the radius and lost energy from a spiral.
COMMON MISCONCEPTION
A pair of tracks springing out of empty space means a particle appeared from nothing.
Only a charged particle ionises, and only ionisation leaves a track, so a neutral parent crosses the chamber unseen and its daughters appear where it decayed. The gap is the evidence for it, not a hole in the picture.
The two laws that always apply
Beyond the quantum numbers, energy and momentum are conserved in every interaction, and either can forbid a process that the quantum numbers allow. A free proton decaying by p → n + e+ + νe would conserve charge, baryon number and electron lepton number. Yet it does not happen. The products' rest energies, about 939.6 MeV plus 0.511 MeV, add up to more than the proton's 938.3 MeV. No energy is available to make up the difference, so the decay is forbidden, and a free proton is stable. Inside a nucleus the energy balance is different, so bound protons can undergo β+ decay where free ones cannot.
Describe the drawing
Two bars drawn to one scale that starts at 930 MeV, so that a small difference can be seen. The upper bar is the proton's rest energy, 938.3 MeV. The lower bar is what the proposed products need, a neutron at 939.6 MeV with a positron on the end of it, and it runs about 1.8 MeV past the dashed line the proton reaches. A free proton has no spare energy to cover that difference, which is why the decay never happens although every quantum number balances.
Momentum forbids processes just as firmly, and the antimatter lesson has already shown it doing so. A lone photon in empty space cannot become an electron-positron pair, however much energy it carries. No arrangement of that pair balances energy and momentum at once. That is why pair production needs a nearby nucleus to take the recoil. Keep the two checks separate. Energy sets whether there is enough available, and momentum sets whether the products can be arranged so that it is conserved.
Reading particle tracks, an Edexcel skill
Interpreting a detector photograph is Edexcel content; the other three boards do not set it. The physics is the same set of conservation checks, applied to a picture instead of an equation.
A detector records a charged particle because the particle ionises whatever it flies through. That trail of ions is made visible, as a string of bubbles in a bubble chamber or as a run of hits in a modern tracker. A neutral particle ionises nothing and so leaves no track at all. Treat the absence as evidence. A pair of tracks appearing out of empty space, with a clear run behind them, means a neutral particle crossed that gap unseen. It is drawn dashed because nobody saw it. A neutral kaon or a Λ0 appears in this way, as a V with nothing leading into it.
Describe the drawing
Two panels. On the left a dashed grey line, a neutral particle leaving no track, ends at a vertex where two curved tracks spring apart: a wide cyan arc curling upward for charge plus one and a tighter amber arc curling downward for charge minus one. On the right a single cyan track spirals inward, its radius shrinking turn by turn as the particle loses energy to the chamber.
A magnetic field across the chamber bends every charged track. The magnetic fields unit equates the magnetic force to the centripetal force to get the radius. It writes the result as r = mv/BQ, and Edexcel writes it as . They are one relation, since p = mv.
Two readings come straight off the photograph. Which way a track curls gives the sign of the charge, once the field direction and the direction of travel are known. Without those, the curl still separates the charges, since opposite signs bend opposite ways in one field. How tightly a track curls gives the momentum: a wide gentle arc means high momentum and a tight one low. The photograph is read in the plane perpendicular to the field, so strictly the radius measures the momentum component in that plane. Speed follows only once the particle is identified. A straight track is simply the wide end of that scale, too much momentum to bend measurably.
A track that spirals is the same rule applied twice. The particle is ionising as it goes, and every ion it makes takes energy from it, so its momentum falls, and by r = p/(BQ) the radius falls with it until the curve winds itself in. So a spiral reads two things at once. This particle is losing energy, and the tight end is the late end. Direction of travel follows from it, which matters more than it looks, because reading the same picture backwards reverses the sign of every charge in it.
At the vertex, apply the same conservation laws to the photograph. Charge is counted by curl: two daughters curling opposite ways carry opposite signs, and if nothing led into the vertex those charges have to cancel exactly. Momentum is a vector sum. Read each daughter's momentum from its radius and point it along its own track; together they must add to the parent's momentum along the invisible line. That is why the two arms of a V straddle that line instead of leaning to one side. Energy is the last check. The parent has to cover the daughters' rest energies, with enough left over for the kinetic energy those momenta imply.
WORKED EXAMPLE
One V, read off the picture
Two tracks spring from a point with nothing leading into it. One curls clockwise on a tight arc and the other anticlockwise on an arc about three times wider, in a uniform field. State what can be deduced about the parent and the two daughters.
Nothing arrives at the vertex, so the parent was neutral: only a charged particle ionises, and only ionisation leaves a track. Its path is real but invisible, running back from the vertex along the direction in which the two daughters' momenta add up.
The daughters curl opposite ways, so they carry opposite signs, and since the parent's charge was zero their charges must cancel exactly rather than merely differ.
Radius is momentum. With one field and equal magnitudes of charge, r = p/(BQ) makes the wider track's momentum about three times the tighter one's.
INDEPENDENT PRACTICE
The track that tightens
A charged particle enters a bubble chamber and its track spirals inwards, tightening turn by turn. A classmate says the spiral shows the particle speeding up, since it is turning faster and faster. Correct them, and say which end of the spiral the particle reached last.
Show the working
Turning faster is not going faster. The radius is r = p/(BQ), so a tightening spiral is a falling momentum, and the particle is being slowed by ionising the liquid it crosses.
The tight end is therefore the late end, reached last. Getting that the right way round fixes the direction of travel, which in turn fixes the sign of the charge, so one misread spiral takes the whole answer with it.
ASSESSMENT FOCUS
- When every quantum number balances and the process still cannot occur, check energy and compare rest energies from the data booklet. That is why a free proton does not decay. If the energy is available and the process still fails, check momentum, which is the lone photon's problem in pair production.
- Edexcel track questions are answered with four fixed sentences, so learn them. No track means the particle was neutral. Direction of curl gives the sign of the charge. Radius gives the momentum through r = p/(BQ). A tightening spiral means energy is being lost to the chamber, and the tight end came last.
- In a track question, settle the direction of travel before you name a single charge, because a photograph read backwards gives every sign the wrong way round. A spiral fixes it for you, and a vertex fixes it too: tracks that spring apart from a point were all made after it.
CHECK YOURSELF
A student proposes that a free proton decays: p → n + e+ + νe. Audit the conservation laws, then explain what actually forbids the decay. (Rest energies: p 938.3 MeV, n 939.6 MeV, e 0.511 MeV.)
Show a hint
Every quantum number balances. So check the one thing left.
Show the answer
Charge runs +1 → 0 + 1 + 0 ✓. Baryon number runs +1 → +1 ✓. Electron lepton number runs 0 → 0 − 1 + 1 = 0 ✓. Strangeness stays at 0 ✓. Every quantum number balances.
Energy does not. The products carry at least 939.6 + 0.511 = 940.1 MeV of rest energy, which is more than the proton's 938.3 MeV, and a free proton has no spare energy to make up the difference.
Energy conservation forbids the decay, and the proton stays the only stable free baryon. Inside a nucleus the binding-energy balance is different, and that difference permits β+ decay there.
Energy and momentum must be conserved as well, and either alone can forbid an interaction.
On a photograph, no track means a neutral particle, the curl gives the sign and the radius gives the momentum.
Or read them with their mark schemes on the conserved quantities questions page.
Or revise the whole particles deck of 54 cards.
CHECK YOUR PROGRESS
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- Recognise that energy and momentum are conserved in every interaction, and that either can forbid one.
- For Edexcel, interpret a particle-track photograph, reading the sign of a charge from the curl, the momentum from the radius and lost energy from a spiral.
Open the full revision checklist to track your progress across the whole unit.
