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Questions on classification of particles
Hadrons are the particles that feel the strong interaction and divide into baryons and mesons, while leptons are fundamental and never feel it. Baryon number and the electron and muon lepton numbers are conserved in every interaction; strangeness is conserved only in the strong interaction, so strange particles are produced in pairs by the strong interaction and decay by the weak.
20 original questions · 55 marks · the classification of particles notes · Particles
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State the two groups into which particles are classified according to whether they experience the strong interaction, and identify which group does.
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Hadrons and leptons (1). Hadrons feel the strong interaction; leptons do not (1). Hadrons are further split into baryons and mesons.Distinguish between a baryon and a meson.
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A baryon is a hadron made of three quarks, baryon number +1, such as the proton or neutron (1). A meson is a hadron made of a quark and an antiquark, baryon number 0, such as a pion or kaon (1).Give two examples of leptons.
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Any two of the following, one mark each (2): the electron; the muon; the electron neutrino; the muon neutrino; or any of their antiparticles.State the number of quarks in a baryon and in a meson.
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A baryon is made of three quarks; a meson is a quark and an antiquark (1).The strong nuclear force between nucleons is carried by an exchange particle. Name this particle and state the class of hadron to which it belongs.
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The pion (1). It is a meson (1).State what a kaon decays into, and name the interaction responsible for the decay.
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A kaon decays into pions (also accept muons and neutrinos) (1). The decay proceeds by the weak interaction (1).State the baryon number of a baryon, an antibaryon and a meson, and explain how baryon number is used.
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Baryon +1, antibaryon −1 (1), meson 0 (1). Baryon number is a conserved quantity: in any allowed interaction the total baryon number before equals the total afterwards (1).State the lepton number of an electron, a positron and an electron antineutrino.
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Electron: Le = +1 (1). Positron: Le = −1 (1). Electron antineutrino: Le = −1 (1).A free neutron decays: n → p + e− + anti-νe. Show that this decay conserves both baryon number and lepton number.
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Baryon number before: 1 (1)
Baryon number after: 1 + 0 + 0 = 1, so it is conserved (1)
Lepton number before: 0 (1)
Lepton number after: 0 + (+1) + (−1) = 0, the electron having Le = +1 and the antineutrino Le = −1 (1)Describe how strange particles are produced and how they decay, and state what this implies about strangeness.
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Strange particles are produced in pairs through the strong interaction (1), but decay through the weak interaction (1). Strangeness is conserved in strong interactions but can change by 0 or ±1 in weak interactions (1).A muon decays by μ− → e− + anti-νe + νμ. Show that both electron lepton number and muon lepton number are conserved in this decay.
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Muon lepton number: 1 → 0 + 0 + 1 = 1 ✓ (1). Electron lepton number: 0 → (+1) + (−1) + 0 = 0 ✓ (1). Each family balances separately, as required, so the decay is allowed (1).A student claims that the muon must be a meson because its mass lies between the mass of the electron and the mass of the proton. Explain why the muon is in fact a lepton.
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Particles are classified by the interactions they experience, not by their mass (1). The muon does not feel the strong interaction (1) and it is fundamental, not made of quarks, so it belongs with the leptons (1).Explain why the proton is the only stable free baryon.
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Baryon number is conserved in every interaction (1), so any decaying baryon must leave a baryon among its products (1). The proton is the lightest baryon, so there is nothing lighter for it to decay into, while every other free baryon eventually decays, in steps, to a proton (1).State two differences between a kaon and a pion.
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A kaon has strangeness +1 or −1, whereas a pion has strangeness 0 (1). Kaons decay into pions, by the weak interaction, whereas the pion is the exchange particle of the strong force between nucleons (1).A proposed interaction is p + e− → n + νe. By checking charge, baryon number and lepton number, state whether it is allowed.
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Charge: (+1) + (−1) = 0 → 0 + 0 = 0, conserved (1)
Baryon number: 1 + 0 = 1 → 1 + 0 = 1, conserved (1)
Lepton number: 0 + (+1) = +1 → 0 + (+1) = +1, conserved (1)
All three are conserved, so the interaction is allowed (1)Classify each of these particles as a baryon, a meson or a lepton: proton, pion, muon, neutron, electron neutrino.
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Proton: baryon. Pion: meson (1). Muon: lepton (1). Neutron: baryon. Electron neutrino: lepton (1).State two properties that distinguish a lepton from a hadron.
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Leptons are fundamental (not made of quarks) (1) and do not feel the strong interaction (1); hadrons are made of quarks and do feel the strong interaction (1).In a cosmic-ray experiment a new particle X is observed. X is only ever created together with a second new particle, in collisions that occur on strong-interaction timescales, but X decays into pions comparatively slowly, with a lifetime of about 10−10 s. Deduce, with reasons, whether X is a strange particle, and name the interaction by which it decays.
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Creation in pairs by the strong interaction is the behaviour of strange particles (1): the strong interaction conserves strangeness, so it can only make strangeness +1 and −1 together (1). The comparatively slow decay shows the decay is by the weak interaction, the only interaction that can change strangeness (1). So X is a strange particle (for example a kaon) and it decays by the weak interaction (1).Explain why the interaction νμ + n → e− + p is never observed, even though it conserves both charge and baryon number.
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Lepton number must be conserved separately for each family (1). Muon lepton number: 1 → 0, so it is not conserved (1). Electron lepton number: 0 → +1, also not conserved; either failure on its own forbids the interaction (1).A particle has baryon number 0, charge −1 and strangeness 0, and it experiences the strong interaction. Deduce its classification, and name a particle it could be.
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It feels the strong interaction, so it is a hadron (1). Its baryon number is 0, so it must be a meson (1). A meson with charge −1 and zero strangeness is the π− (1).
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