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Questions on quarks and the hadrons built from them
Every hadron on this course is built from up, down and strange quarks, a baryon from three of them and a meson from a quark with an antiquark. The proton is uud and the neutron udd, while the pions and kaons are quark-antiquark pairs. Adding up the quarks' values checks a composition for charge, baryon number and strangeness, or deduces one.
27 original questions · 78 marks · the quarks and the hadrons built from them notes · Particles
To print: the questions (PDF, 90 KB) · the worked answers (PDF, 85 KB)
These questions cover both lessons on quarks and antiquarks: Quarks and the hadrons built from them and Decays at quark level.
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State the electric charge of the up quark and of the down quark, as fractions of the elementary charge e.
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Up quark: +2/3 e (1). Down quark: −1/3 e (1).State the quark composition of a proton and of a neutron.
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Proton: up, up, down (uud) (1). Neutron: up, down, down (udd) (1).State the baryon number of a quark and of an antiquark.
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A quark has baryon number +1/3 (1); an antiquark has −1/3 (1).State the strangeness of the strange quark and of the anti-strange quark.
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Strange quark: strangeness −1 (1). Anti-strange quark: strangeness +1 (1).The π− is the antiparticle of the π+ (up, anti-down). State the quark composition of the π− and show that its charge is −1e.
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The π− is a down quark and an anti-up quark (1). Charge = (−1/3) + (−2/3) = −1e (1).State two properties of a quark that take the opposite sign for its antiquark.
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Charge (1); baryon number or strangeness (1). (Any two of the three.)In beta-minus decay a down quark changes into an up quark, and in beta-plus decay an up quark changes into a down quark. State the charge of the W boson emitted in each case.
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Beta-minus: the W boson carries charge −1, so it is a W− (1). Beta-plus: the W boson carries charge +1, so it is a W+ (1).Name the only fundamental interaction that can change the flavour of a quark, and state what follows for the strangeness of the particles in a strong interaction.
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The weak interaction (1). Because no other interaction changes quark flavour, a strong interaction cannot change the number of strange quarks present, so strangeness is conserved exactly in it (1).Show, using the quark charges, that a proton (uud) has a charge of +1e.
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Charge = (+2/3) + (+2/3) + (−1/3) (1)
= +3/3 = +1e (1)Show, using the quark charges, that a neutron (udd) has a charge of 0.
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Charge = (+2/3) + (−1/3) + (−1/3) (1)
= 0 (1)A positive pion is made of an up quark and an anti-down quark. Calculate its charge and its baryon number, showing your working.
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Charge = (+2/3) + (+1/3) (1)
= +1e (the anti-down quark has charge +1/3) (1)
Baryon number = (+1/3) + (−1/3) (1)
= 0, confirming it is a meson (1)State the quark composition of an antiproton and show that its charge is −1e.
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An antiproton is anti-up, anti-up, anti-down (1)
Charge = (−2/3) + (−2/3) + (+1/3) (1)
= −3/3 = −1e (1)The Δ++ baryon has charge +2e, baryon number +1 and strangeness 0. Deduce its quark composition, showing your reasoning. Quark charges: up +2/3 e, down −1/3 e.
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Baryon number +1 means three quarks (1). With strangeness 0, only up (+2/3) and down (−1/3) are available, and the only trio whose charges sum to +2 is three up quarks (1). Check: 3 × (+2/3) = +2e, so the composition is uuu (1).In beta-minus decay a down quark changes into an up quark, emitting a W− boson. Show that charge is conserved at this vertex.
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Before: the down quark has charge −1/3. After: up (+2/3) + W− (−1) (1). (+2/3) + (−1) = −1/3, equal to the charge before, so charge is conserved (1).Explain, in terms of quark content, why kaons have strangeness +1 or −1 but pions always have strangeness 0.
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Each kaon contains exactly one strange or one anti-strange quark (1): an anti-strange quark gives the kaon strangeness +1 and a strange quark gives strangeness −1 (1). Pions are built only from up and down quarks and their antiquarks, all of which have strangeness 0 (1).The beta-minus decay of a neutron is written at quark level as d → u + e− + anti-νe. Show that baryon number and electron lepton number are both conserved at this vertex.
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Baryon number before = +1/3, the baryon number of one quark (1)
After = +1/3 for the up quark, and 0 for the electron and the antineutrino, giving +1/3, so baryon number is conserved (1)
Electron lepton number: 0 before; after = (+1) for the electron + (−1) for the electron antineutrino = 0, so it is conserved as well (1)A Ξ− baryon has quark content dss. It decays into a Λ0 (uds) and a π− (a down quark and an anti-up quark). The strange quark has charge −1/3 e and strangeness −1; the up quark has charge +2/3 e. Determine the quark that changes flavour, the charge of the W boson emitted, and the interaction responsible.
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One strange quark becomes an up quark, s → u; the other strange quark and the down quark are spectators (1)
Charge at the vertex: −1/3 → +2/3 plus the W, so the W carries −1 and is a W− (1)
Strangeness runs −2 → −1, and only the weak interaction changes quark flavour, so the decay is weak (1)A student writes the quark change in beta-plus decay as u → d + W−. Explain, using the quark charges, why the boson emitted must be a W+ instead, and state what that boson becomes.
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The up quark has charge +2/3 and the down quark −1/3 (1)
The quark gives up (+2/3) − (−1/3) = +1 of charge, so the boson must carry +1, which is a W+ and not a W− (1)
The W+ becomes a positron and an electron neutrino (1)Describe the beta-minus decay of a neutron in terms of its quarks, naming what the changed quark becomes and the particles emitted.
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Inside the neutron (udd) one down quark changes into an up quark (1), turning it into a proton (uud) (1). The change emits a W− boson (1), which becomes an electron and an electron antineutrino (1).A positive kaon is made of an up quark and an anti-strange quark. The anti-strange quark has charge +1/3 e and strangeness +1. Determine the charge and the strangeness of the K+, showing your working.
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Charge = (+2/3) + (+1/3) (1)
Charge = +1e (1)
Strangeness = 0 (up) + (+1) (anti-strange) = +1 (1)Explain why the quark model assigns the neutron the composition udd rather than uud.
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The composition must give the neutron's zero charge (1). uud gives +1e (the proton) (1), whereas udd gives (+2/3) + (−1/3) + (−1/3) = 0, matching the neutral neutron (1).A baryon has charge 0 and strangeness −1. Deduce its quark composition, using only up, down and strange quarks. Quark charges: up +2/3 e, down −1/3 e, strange −1/3 e; the strange quark has strangeness −1.
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A baryon is three quarks, with no antiquarks (baryon number +1) (1). Strangeness −1 means exactly one strange quark, contributing charge −1/3 (1). The other two quarks must supply +1/3 between them, which one up (+2/3) and one down (−1/3) do (1). Composition: uds, with charge (+2/3) + (−1/3) + (−1/3) = 0 ✓ (1).A student claims to have detected a baryon with charge +1 and strangeness +1. Deduce whether such a particle can be built from up, down and strange quarks and their antiquarks. The strange quark has strangeness −1 and baryon number +1/3; an antiquark has baryon number −1/3.
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A baryon has baryon number +1, so it must contain three quarks and no antiquarks, since each antiquark contributes −1/3 (1). Among the up, down and strange quarks, only the strange quark carries strangeness, and its value is −1; the anti-strange quark (+1) is not available inside a baryon (1). A baryon's strangeness can therefore only be 0, −1, −2 or −3, never +1 (1). The claim is impossible: no such particle exists in the quark model (1).State the maximum possible charge of a baryon built from up, down and strange quarks, and explain your reasoning. Quark charges: up +2/3 e, down −1/3 e, strange −1/3 e.
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The up quark has the largest charge, +2/3 e (1). A baryon is three quarks, so the maximum charge is that of uuu: 3 × (+2/3) = +2e (1). Replacing any up with a down or a strange quark (both −1/3 e) lowers the total, so +2e is the maximum (1).A proton bound in a nucleus decays by beta-plus emission. Describe this decay in terms of the proton's quarks, naming what the changed quark becomes, the boson emitted and the particles that boson becomes.
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Inside the proton (uud) one up quark changes into a down quark (1), turning it into a neutron (udd) (1). The change emits a W+ boson (1), which becomes a positron and an electron neutrino (1).A Λ0 baryon (uds) decays into a proton (uud) and a π− (a down quark and an anti-up quark). Explain why this decay cannot proceed by the strong interaction, and state what this implies about the lifetime of the Λ0 compared with that of a particle which decays by the strong interaction.
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Writing the quark content under both sides, the up and the down quark spectate and the strange quark must become an up quark, s → u, which is a change of flavour (1)
The strong interaction conserves quark flavour, and so conserves strangeness exactly, and cannot bring that change about (1)
Strangeness runs −1 → 0, a change of 1, which only the weak interaction allows (1)
The weak interaction is far less probable, so the Λ0 is comparatively long-lived beside a particle that decays by the strong interaction (1)A K0 meson is a down quark with an anti-strange quark, and it decays into a π+ (an up quark with an anti-down quark) and a π− (a down quark with an anti-up quark). The anti-strange quark has charge +1/3 e and strangeness +1; the anti-up quark has charge −2/3 e. Deduce which quark or antiquark changes flavour and what it becomes, the charge of the W boson emitted and what that boson becomes, and the change in strangeness.
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The K0's down quark is a spectator: it appears again in the π− (1)
So it is the anti-strange quark that changes flavour, becoming the anti-up quark that pairs with it to make the π− (1)
Charge: +1/3 → −2/3 plus the W, so the W carries +1 and is a W+ (1)
That W+ becomes the up quark and the anti-down quark of the π+ (1)
Strangeness runs +1 → 0, a change of 1, so this is a weak decay (1)
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