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Further Mechanics 1 formulae

The 8 results the Further Mechanics 1 notes display, each with the conditions it needs to be true and a link to the lesson that states it. The formulae booklet prints none of them, so every one is yours to carry into the examination in your head.

Further Maths · 6 lessons with formulae.

A result the Edexcel formulae booklet prints is marked as such; one it does not print is marked to learn; and a result badged derived in the lesson is a working line the notes build in front of you rather than a standard result to memorise.

6 lessons

Momentum and impulse

I=Ft=mv-mu\text{I} = \text{F}t = m\text{v} - m\text{u}NOT IN THE BOOKLET: LEARN ITConditionsA constant force acting for time t on a constant mass, with one positive direction fixed along the line.
m1u1+m2u2=m1v1+m2v2m_{1}u_{1} + m_{2}u_{2} = m_{1}v_{1} + m_{2}v_{2}NOT IN THE BOOKLET: LEARN ITConditionsNo external impulse on the pair during the collision, and all velocities measured along the same line with one sign convention.

Impulse and momentum as vectors

I=mv-mu\text{I} = m\text{v} - m\text{u}NOT IN THE BOOKLET: LEARN ITConditionsConstant mass, with the vectors resolved in the same pair of directions throughout.

Work, energy and power

KE=12mv2,GPE=mgh\text{KE} = \frac{1}{2}mv^{2}, \qquad \text{GPE} = mghNOT IN THE BOOKLET: LEARN ITConditionsGPE is measured from a stated reference level; KE uses speed, so direction does not enter it.
P=FvP = FvNOT IN THE BOOKLET: LEARN ITConditionsF the driving force along the direction of motion, and v the instantaneous speed.

Hooke's law and elastic strings

T=λxlT = \frac{λ x}{l}NOT IN THE BOOKLET: LEARN ITConditionsAn elastic string or spring of natural length l with x the extension. A string goes slack rather than pushing, so T = 0 when it is shorter than its natural length; a spring pushes, with x the compression.

Elastic potential energy

EPE=λx22l\text{EPE} = \frac{λ x^{2}}{2l}NOT IN THE BOOKLET: LEARN ITConditionsThe same string or spring, x the extension or compression, and the deformation within the elastic limit.

Direct impact and Newton's law of restitution

e=speed of separationspeed of approache = \frac{\text{speed of separation}}{\text{speed of approach}}NOT IN THE BOOKLET: LEARN ITConditionsDirect impact along the line of centres, with 0 ≤ e ≤ 1 and speeds measured along that line.

Every formula in the library is indexed by unit on the equation index, and the Further Mechanics 1 notes are where these results are derived and used. The 8 the booklet does not print are on the list of every formula to memorise, alongside the rest of the course.

Also: Further Statistics 2 formulae · Further Mechanics 2 formulae