Physics › Electronics › Modulation and PCM

Modulation and PCM

Amplitude modulation by one tone sends three frequencies, the carrier and one sideband each side, so an AM station occupies a bandwidth of 2fM. Frequency modulation swings the carrier instead and takes 2(Δf + fM), buying immunity to amplitude noise. Pulse-code modulation sends sampled levels as binary.

Data communication, part 1 of 2. Part 2 is Radio propagation and data security.

Builds on Combinational logic and Progressive waves.

IN THIS TOPIC

  • Distinguish baseband from modulated transmission, and say what a carrier achieves.
  • Find sideband frequencies and bandwidth for AM, and bandwidth for FM.
  • Weigh AM against FM on bandwidth, noise and cost.
  • Choose a sampling rate, and follow a signal through pulse-code modulation.

COMMON MISCONCEPTION

FM radio sounds cleaner than AM because it is broadcast at higher power.

The advantage lies in what the receiver reads. Noise adds to a wave's amplitude; an FM receiver clips the amplitude flat and detects only the frequency, so nearly all of that noise is removed, and the wide FM channel also carries audio to 15 kHz.

Baseband, and the case for a carrier

Send a signal in its own natural range of frequencies and you are transmitting at baseband. A telephone landline does exactly this, speech from about 300 Hz to 3.4 kHz travelling down a private pair of wires, and on a private wire baseband is fine. Radio has no private wires. Every transmitter shares the same air, and if each station broadcast baseband audio they would all occupy the same few kilohertz and land on top of one another.

An audio-frequency radio signal has a wavelength that would require an impractically large resonant aerial, and different broadcasts would be difficult to separate if transmitted at baseband. Modulation uses the information signal to vary a high-frequency carrier. Amplitude modulation varies the carrier amplitude; frequency modulation varies its instantaneous frequency. Pulse-code modulation represents regularly sampled values as binary numbers.

The numbers make the aerial point concrete. An efficient resonant aerial is a substantial fraction of a wavelength long, and a 3 kHz radio wave is 100 km long, so a resonant aerial for it would be impractically large; electrically short aerials can be built, but they are inefficient. A carrier's much shorter wavelength suits a real aerial, and each station is allotted its own carrier frequency, so a tuned circuit at the receiver can select one station and reject the rest.

Amplitude modulation

Amplitude modulation keeps the carrier frequency fcf_{c} fixed and makes its amplitude follow the programme, loud passages swelling the envelope. The surprise is what this does to the spectrum. Modulate a carrier with a single audio tone of frequency fMf_{M} and you transmit exactly three frequencies, the carrier itself plus two sidebands at fc+fMf_{c} + f_{M} and fc-fMf_{c} - f_{M}. The audio is not sent at its own frequency; it appears as the pair of new frequencies flanking the carrier.

The spectrum of an amplitude-modulated carrier: the carrier with one sideband either side, and a bandwidth of twice the modulating frequency
Describe the drawing

A frequency axis carrying three vertical lines: a tall carrier at nine hundred and nine kilohertz with a shorter sideband four and a half kilohertz below it at nine hundred and four point five, and another the same distance above at nine hundred and thirteen point five. A double-headed arrow beneath spans the two sidebands and is labelled bandwidth equals twice the modulating frequency, nine kilohertz.

FIG. 1The spectrum of a carrier amplitude-modulated by one audio tone: a tall line at the carrier frequency, one sideband spaced f M below it and one f M above it, and the occupied width running from the lower sideband to the upper, twice f M.

Real programmes are a band of tones up to some maximum audio frequency fMf_{M}, so each sideband spreads into a band, and the transmission occupies everything from fc-fMf_{c} - f_{M} to fc+fMf_{c} + f_{M}. The occupied width is the bandwidth:

AM bandwidth=2fM\text{AM bandwidth} = 2f_{M}IN THE AQA DATA BOOKLET

WORKED EXAMPLE

Medium wave arithmetic

A medium-wave station on a 909 kHz carrier transmits audio limited to 4.5 kHz. Find the frequencies it occupies and its bandwidth.

Sidebands run from 909 − 4.5 = 904.5 kHz up to 909 + 4.5 = 913.5 kHz.

The bandwidth is 2 × 4.5 = 9.0 kHz, and medium-wave stations are duly spaced 9 kHz apart across the band.

The audio ceiling of 4.5 kHz is the consequence of that tight packing. Music loses its top octaves before it ever leaves the transmitter.

Frequency modulation

Frequency modulation holds the amplitude constant and swings the carrier's frequency instead, above and below fcf_{c} in step with the programme. Louder audio swings it further; the maximum swing is the frequency deviation Δf\Delta f. An FM signal's sidebands in fact trail off indefinitely, so the occupied bandwidth is estimated by Carson's rule, which allows the deviation plus the highest modulating frequency on each side of the carrier:

FM bandwidth=2(Δf+fM)\text{FM bandwidth} = 2(\Delta f + f_{M})IN THE AQA DATA BOOKLET

WORKED EXAMPLE

Broadcast FM bandwidth

A broadcast FM station uses a deviation of 75 kHz and carries audio up to 15 kHz. Find its bandwidth, and compare it with the medium-wave station's.

Bandwidth = 2 × (75 + 15) = 180 kHz.

That is twenty times the 9 kHz an AM station occupies. FM achieves its quality by using more spectrum, and the wide channels only fit because the FM band sits up near 100 MHz, where there is room.

Noise, whether from motors, lightning or distant sparks, adds to a wave's amplitude. An AM receiver reads the amplitude, so it faithfully reproduces the noise. An FM receiver reads only the frequency, and it clips the amplitude flat before detection, removing most amplitude noise. Noise that disturbs the wave's apparent frequency or phase survives in smaller measure, and the advantage holds only while the signal stays comfortably above the receiver's working threshold.

A tone sent by amplitude modulation and by frequency modulation, and the same burst of amplitude noise added to each: the AM envelope carries the burst through, and the FM zero crossings do not move
Describe the drawing

Five traces one above the other, all against the same stretch of time. At the top is one cycle of the modulating tone. Below it the carrier amplitude-modulated by that tone, its dashed envelope swelling to A times one plus m at the tone's peak and shrinking to A times one minus m at the trough. Below that the same wave with a short burst of amplitude noise added, the coral envelope lifted clear of the dashed one where the burst lands. The fourth trace is the same tone sent by frequency modulation: the height never changes and the cycles are visibly crowded together where the tone peaks and stretched apart where it dips. The last trace is that FM signal with the same burst added and the receiver's limiter applied, its peaks flattened where the burst was, and the dashed verticals show that the zero crossings sit at exactly the instants they did before. AM writes the programme where noise lives, in the amplitude; FM writes it in the frequency, which a limiter can clean.

FIG. 2One tone written onto one carrier both ways, and then a burst of amplitude noise added to each. The AM envelope swells and shrinks with the tone, so the burst joins the programme and is heard; the FM wave keeps one height throughout and carries the tone as cycles crowded together at the tone's peak and stretched apart at its trough, so the limiter can cut the burst away and leave every zero crossing where it was.

FM also carries audio to 15 kHz rather than 4.5, and its constant amplitude lets the transmitter run steadily at full efficiency. AM's advantage is economy, a twentieth of the spectrum per station and receivers simple enough to build with a diode.

AMFM
bandwidth per stationnarrow, 2fM2f_{M}, about 9 kHzwide, 2(Δf+fM)2(\Delta f + f_{M}), about 180 kHz
response to noisenoise adds to amplitude, and is heardamplitude clipped flat, so most noise is removed
audio qualitylimited, about 4.5 kHz of audioup to 15 kHz of audio
transmitter and receiversimple and cheapmore complex circuitry
carrier frequencies usedlong and medium wave, longer rangeVHF, roughly line of sight

GUIDED PRACTICE

A narrowband compromise

A marine two-way radio uses FM with a deviation of 2.5 kHz and speech limited to 3.0 kHz. Find its bandwidth, and explain in one sentence why it accepts a far smaller deviation than broadcast FM.

Show the working

Bandwidth = 2 × (2.5 + 3.0) = 11 kHz.

Small deviation keeps each channel narrow, so many ships share the band; speech only needs to be intelligible, not high fidelity, and the noise advantage of FM survives in miniature.

Sending numbers instead: sampling and PCM

A digital signal resists noise and can be regenerated without loss. To give an analogue signal those advantages, digitise it. Step one is sampling, measuring the signal's value at regular instants. Sample too rarely and wiggles between samples are missed entirely. The rule has a sharp edge: the sampling rate must be greater than twice the highest frequency present in the signal. Sampled slower than that, a high frequency masquerades as a low one and the corruption cannot be undone afterwards.

Sampling and quantisation: the wave is measured at regular instants, each sample is rounded to one of eight levels, and three bits name the level
Describe the drawing

A sine wave crossing eight dashed horizontal levels labelled with the three-bit codes 000 to 111. Cyan dots mark twelve equally spaced samples taken on the wave, each joined by a short stem to the amber dot on the nearest level, and the sequence of three-bit codes those levels give is printed underneath as the transmitted bit stream.

FIG. 3An analogue wave sampled at regular instants, each sample rounded to the nearest of eight quantisation levels. Three bits name each level, and the resulting bit stream is the wave as pulse-code modulation.

Step two is quantisation. Each sample is rounded to the nearest of 2n2^{n} fixed levels, and the level is named by an n-bit binary code. The rounding error is the quantisation error, shrunk by adding bits, since each extra bit doubles the number of levels and halves the step between them. The stream of codes, sent as pulses, is pulse-code modulation, PCM. From that point the signal has the advantages of a digital signal, regeneration included, so noise stops accumulating along the route.

WORKED EXAMPLE

The telephone's budget

Telephone speech is limited to 3.4 kHz, sampled at 8.0 kHz with 8 bits per sample. Check the sampling rate and find the bit rate.

Twice the highest frequency is 6.8 kHz, and 8.0 kHz clears it, with margin left for imperfect filters.

Bit rate = 8000 samples per second × 8 bits = 64 000 bits per second, the standard worldwide figure for one digital phone call.

Ground wave, sky wave, space wave has moved to the next part of this lesson.

Up to the satellite and back down has moved to the next part of this lesson.

Sharing the channel, choosing the medium has moved to the next part of this lesson.

Who else is listening has moved to the next part of this lesson.

ASSESSMENT FOCUS

  • A carrier modulated by one tone transmits three frequencies, the carrier and one sideband each side. Quote all three.
  • Bandwidth is the full occupied width, 2fM2f_{M} for AM, never fMf_{M}. Halving it gives the spacing of one sideband from the carrier rather than the bandwidth.
  • Keep kHz and MHz apart. Convert the audio frequency and the carrier to the same unit before adding or subtracting, and check the sidebands sit close to the carrier, not at it.
  • FM bandwidth needs both terms, 2(Δf+fM)2(\Delta f + f_{M}). Include the highest modulating frequency fMf_{M} as well as the deviation.
  • State the sampling rule with its inequality, more than twice the highest signal frequency, and multiply samples per second by bits per sample for any bit-rate mark.

CHECK YOURSELF

A station broadcasts speech limited to 4.0 kHz by AM on a 1.2 MHz carrier. Find the range of frequencies transmitted and the bandwidth. A rival carries the same speech by FM with a deviation of 6.0 kHz. Find the FM bandwidth, and state one advantage each listener holds over the other. The AM station then digitises the same speech, sampling at 9.0 kHz with 8 bits a sample: check the rate is adequate and find the bit rate.

Show a hint

Convert the carrier to kHz first. AM occupies fc − fM up to fc + fM; FM needs the deviation as well. The sampling rate must clear twice the highest audio frequency, and the bit rate is samples per second times bits per sample.

Show the answer

The carrier is 1200 kHz, so the transmission runs from 1196 kHz to 1204 kHz, a bandwidth of 2 × 4.0 = 8.0 kHz.

FM bandwidth = 2 × (6.0 + 4.0) = 20 kHz, two and a half times the spectrum per station.

The FM listener hears less noise, because the receiver clips away amplitude disturbances. The AM listener's station spends far less bandwidth, so more stations fit in the band, and the receiver is simpler and cheaper.

Twice the highest audio frequency is 8.0 kHz, and 9.0 kHz clears it, so no frequency is aliased. The bit rate is 9000 × 8 = 72 000 bits per second.

One modulating tone makes three frequencies, so AM occupies 2fM of spectrum while FM occupies 2(Δf + fM) and shrugs off amplitude noise.

Sample faster than twice the highest frequency, round to a level, send the code: PCM.

WORKBOOK

Printable practice for this topic: original exam-style questions with room to work, and a fully worked answer book. Free to use; please do not redistribute or sell.

15 questions on this topicAnswer them one at a time and mark yourself against the mark scheme.Practise this topic

Or read them with their mark schemes on the modulation and PCM questions page.

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  • Distinguish baseband from modulated transmission, and say what a carrier achieves.
  • Find sideband frequencies and bandwidth for AM, and bandwidth for FM.
  • Weigh AM against FM on bandwidth, noise and cost.
  • Choose a sampling rate, and follow a signal through pulse-code modulation.

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