Physics › Electronics › Zener diodes and semiconductor sensors
Zener diodes and semiconductor sensors
A zener diode broken down in reverse holds a supply rail near its breakdown voltage, while a series resistor drops whatever the supply leaves. Two sensors follow. A reverse-biased photodiode's photocurrent is proportional to illumination, and a Hall sensor's output voltage to magnetic flux density.
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Discrete semiconductor devices, part 2 of 2. Part 1 is The MOSFET as a switch.
Builds on The MOSFET as a switch and Current-voltage characteristics and Force on a moving charge.
IN THIS TOPIC
- Use a zener diode and its series resistor to hold an output steady against a wandering supply.
- Say what a photodiode and a Hall effect sensor each measure, and choose between a photodiode and an LDR.
COMMON MISCONCEPTION
A diode that conducts in reverse is a diode that has failed.
Reverse conduction is the job, not a fault: run past its breakdown voltage a zener conducts in reverse while holding its terminal pd almost constant at VZ, and a series resistor takes the rest of the supply. That steady pd is the regulator.
Holding a rail steady
Each of the three devices here converts a physical quantity into a voltage or a current that the rest of a circuit can use: a zener diode holds a supply rail near its breakdown voltage, a photodiode produces a current proportional to illumination, and a Hall sensor produces a voltage proportional to magnetic flux density.
Run an ordinary diode backwards and it blocks until the reverse voltage grows large enough to destroy it. A zener diode is built to break down gently at a chosen voltage and to survive the experience indefinitely, so long as its rated current and power are respected. Past breakdown its characteristic is nearly vertical, so the current through it can swing by tens of milliamps while its pd barely moves.
A component whose voltage stays almost constant is what a supply rail needs. So the zener goes across the load, reverse biased, with a series resistor between it and the raw supply. The load gets , everything left over is dropped across the resistor, and when the supply wanders it is the resistor's share that changes.
The resistor sets the current, and the current is what the design turns on:
Too small a current and the diode never properly reaches breakdown. Too large and it overheats. In the figure the resistor carries 10.0 mA at 9 V in and 25.4 mA at 15 V in, and the zener carries whatever the load leaves.
GUIDED PRACTICE
Sharing the current
The regulator above runs from 12 V. Find the current in the 390 Ω resistor, then the current in the zener when the load draws 8.0 mA, and the power the zener dissipates.
Show the working
The resistor drops 12 − 5.1 = 6.9 V, so it carries 6.9/390 = 17.7 mA.
The load takes 8.0 mA of that, leaving 17.7 − 8.0 = 9.7 mA in the zener, and a power of 5.1 × 9.7 × 10−3 = 49 mW.
Ask the load for more than 17.7 mA and the zener current would have to run backwards, which it cannot. The output sags below 5.1 V and regulation is lost.
Light into current
A photodiode is a diode with a window, used reverse biased so that almost nothing flows in the dark. A photon absorbed in the depletion layer frees an electron-hole pair, and the strong field there sweeps the two apart before they can recombine. Every absorbed photon therefore adds to a small reverse current, the photocurrent, and doubling the illumination doubles the pairs freed each second.
Those flat lines carry two messages. Photocurrent is proportional to illumination, so a single constant, the responsivity, describes the device where a curved characteristic would have needed a whole calibration graph. That is not the same as needing no calibration at all. The constant itself still has to be found against a known source, and it depends on the wavelength of the light, differs from one device to the next and drifts with temperature, while the small dark current that flows with no light on the window has to be subtracted as well. Linearity makes the calibration short, not unnecessary.
The second message is that the current hardly depends on the applied pd, so the diode behaves as a current source. Read it by dropping its current across a resistor: 40 μA through 50 kΩ gives 2.0 V, and 60 μA gives 3.0 V.
Against a light-dependent resistor the photodiode wins on speed and on linearity. Carriers in an LDR take milliseconds to build up and longer to disperse, so it cannot follow anything flickering faster than a few hundred hertz, and its resistance is nowhere near proportional to the light. A photodiode responds in nanoseconds, which puts one at the end of every optical fibre. Where the light changes slowly, the cheaper LDR is fine.
Measuring a field, and noticing a magnet
Send a current along a thin slab of semiconductor and put a magnetic field through its face. Each moving carrier feels a force at right angles to both, so carriers pile up along one edge and leave the opposite edge short of them. The separated charge builds a field that opposes further pile-up, and matters settle once the two forces balance. What remains is a steady Hall voltage across the faces.
Hold the current constant and that voltage is proportional to the flux density, so the slab is a direct-reading field meter. A Hall probe is exactly that, calibrated. Its reading is largest when the field runs perpendicular to the slab's face, so a probe is rotated for a maximum before the number is taken. The sensor above gives 2.4 mV in 0.20 T and 4.8 mV in 0.40 T, a sensitivity of 12 mV per tesla.
INDEPENDENT PRACTICE
Counting the shaft round
That sensor is mounted beside a rotating shaft carrying one small magnet, which brings 0.35 T past the slab once per revolution. Find the peak output, and explain how the circuit measures the rotation rate.
Show the working
The sensitivity is 2.4/0.20 = 12 mV T−1, so 0.35 T gives 12 × 0.35 = 4.2 mV.
Away from the magnet the field is near zero and so is the output, so the sensor delivers one pulse per revolution. Counting pulses per second gives the rotation rate.
The same sensor detects proximity without any rotation: the output voltage appears when a magnet is brought close to the slab and falls to near zero when it is removed, with no contacts to wear out.
ASSESSMENT FOCUS
- Zener answers begin with the resistor's drop, supply minus , then Ohm's law. The zener current is the resistor current minus the load current, and regulation holds only while that difference stays positive.
- Include the terms reverse biased and proportional to intensity in a photodiode answer. Compare a photodiode with an LDR on response time and on linearity rather than on cost alone.
- A photodiode is read as a current source. Drop its photocurrent across a load resistor and the output pd is IR, so doubling the illumination doubles the reading, and the resistor value sets the scale.
- A Hall probe answer needs three statements: the current through the slab is held constant, the output voltage is proportional to the flux density, and the probe is rotated until the reading is a maximum so that the field lies perpendicular to its face.
CHECK YOURSELF
A 6.2 V zener diode is fed through a 270 Ω series resistor from a 12 V supply, and the load across the zener draws 10 mA. Find the current in the resistor, the current in the zener and the power the zener dissipates, and state what happens if the load tries to draw 25 mA.
Show a hint
The resistor's drop is the supply minus . The zener takes whatever the load leaves.
Show the answer
The resistor drops 12 − 6.2 = 5.8 V, so it carries 5.8/270 = 21.5 mA.
The load takes 10 mA of that, leaving 21.5 − 10 = 11.5 mA in the zener.
The zener dissipates 6.2 × 11.5 × 10−3 = 71 mW.
A load demanding 25 mA asks for more than the resistor can deliver, so the zener current would have to run backwards, which it cannot. The output sags below 6.2 V and regulation is lost.
A zener holds its breakdown voltage across the load while the series resistor drops whatever is left.
Photocurrent follows the light; the Hall voltage follows the flux density.
Or read them with their mark schemes on the mosfet as a switch questions page.
CHECK YOUR PROGRESS
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- Use a zener diode and its series resistor to hold an output steady against a wandering supply.
- Say what a photodiode and a Hall effect sensor each measure, and choose between a photodiode and an LDR.
Open the full revision checklist to track your progress across the whole unit.