Physics › Medical physics › The ear and the transmission of sound

The ear and the transmission of sound

The ossicles act as a lever and the oval window has a fraction of the eardrum's area, so the middle ear raises pressure without adding energy. That step-up is what drives the vibration into the fluid of the cochlea. Along the basilar membrane each frequency disturbs its own region, so position codes pitch.

The physics of the ear, part 1 of 2. Part 2 is Intensity, loudness and the decibel scale.

Builds on Progressive waves and Longitudinal and transverse waves and Stationary waves in air columns.

IN THIS TOPIC

  • Describe the transmission of sound through the outer, middle and inner ear.
  • Explain why the middle ear raises the pressure before the sound reaches the cochlea.

COMMON MISCONCEPTION

The middle ear amplifies sound by adding energy to the wave.

The middle ear adds no energy: the ossicles are a passive lever, and the pressure rises because roughly the same force is delivered from the large eardrum to the much smaller oval window. Amplification of pressure, not of power.

Air, bone, fluid

Everything the brain will ever learn about a sound leaves the ear as nerve impulses from an organ full of fluid, and the sound itself arrives as a pressure variation in air. Getting from one to the other is a transmission problem, and the structure of the ear is the solution to it.

The ear is a chain of three sections, and each one hands the vibration to the next in a different medium. The outer ear is the visible pinna, which collects sound and funnels it into the ear canal. The canal is a tube closed at the far end by the eardrum, and like any closed pipe it resonates. Its first resonance falls near 3 kHz, which is one reason the ear is at its most sensitive there: a canal about 2.5 cm long fits a quarter of a wavelength between the open air and the drum, so it picks out λ = 4L ≈ 10 cm, and sound of that wavelength in air is a frequency of roughly 3 kHz.

At the end of the canal the eardrum vibrates with the arriving pressure variation. That is the boundary of the middle ear, an air-filled cavity spanned by three small linked bones, the ossicles, which carry the motion across to a much smaller membrane called the oval window.

A left-to-right schematic of the ear: pinna and canal collecting sound in air, the eardrum driving three linked ossicle bones as a lever, and the oval window passing the vibration into the fluid-filled cochlea.
FIG. 1Sound in air is collected by the pinna, moves the eardrum, is carried across the middle ear by the three ossicles, and enters the fluid of the cochlea through the much smaller oval window.

The pressure step-up in the middle ear

Two things happen on the way across, and both raise the pressure. The ossicles are linked as a lever, so the force at the far end is larger than the force at the near end. More importantly the eardrum has perhaps twenty times the area of the oval window, and the same force spread over a twentieth of the area is twenty times the pressure. Together they lift the pressure by a factor of the order of twenty or thirty.

That pressure increase is what the next stage needs. Beyond the oval window lies the inner ear, and the cochlea inside it is full of fluid. Sound passing straight from air to fluid would meet a huge mismatch and almost all of it would reflect, exactly as an ultrasound pulse reflects at an air gap. The middle ear is the matching stage that gets the energy across.

The mismatch has a name this option meets again. In ultrasound imaging the same problem is written as a difference in acoustic impedance, and the answer there, the coupling gel between probe and skin, does the same job the middle ear does here: it stops the wave meeting an air-to-something boundary that would send it straight back.

The middle ear does not supply energy: in the idealised account, it increases pressure at the expense of displacement amplitude and improves energy transfer from air to the fluid of the cochlea. Describe this as pressure transformation rather than as active power amplification.

The middle ear as a pressure step-up: a 55 square millimetre eardrum, a lever of arms 1.5 to 1, and a 3.0 square millimetre oval window, so the pressure is raised 27.5 times while the energy carried across each cycle is unchanged
Describe the drawing

The middle ear drawn from the lesson's own numbers. On the left the eardrum, on the right the oval window, the two squares drawn in the true ratio of their areas, 55 square millimetres against 3.0. Between them the ossicles are drawn as a lever whose arms are in the ratio 1.5 to 1, so the force arriving as F leaves as 1.5F, and the two arrows are drawn in that ratio too. Beneath, the pressure at each membrane as a bar: the second is 27.5 times the first, which is the lever's 1.5 multiplied by the area ratio of 55 to 3.0. Beneath that, the energy carried across in one cycle at each end, drawn as two bars of exactly the same length, because the larger force moves through a proportionately smaller distance. A large, easily moved membrane concentrating its force onto a small one raises the pressure and adds no energy at all, so the middle ear steps up pressure and is not an amplifier.

FIG. 2The worked geometry drawn to scale. The eardrum and the oval window are drawn in the true ratio of their areas, 55 mm² against 3.0, with the ossicles between them as a lever of arms 1.5 to 1, so a force F arrives as 1.5F. The pressure bars beneath come out 1 against 27.5, and the energy bars beneath those come out level with each other, because the larger force moves through a proportionately smaller distance.

WORKED EXAMPLE

The pressure gain, from the geometry

An eardrum has an area of 55 mm2 and the oval window an area of 3.0 mm2. The lever action of the ossicles multiplies the force by 1.5. Estimate the factor by which the pressure of the vibration is raised across the middle ear.

The sound exerts a force F on the eardrum, and the ossicles deliver 1.5F to the oval window.

Pressure is force over area, so the gain is the force factor times the area ratio: 1.5 × 55/3.0 = 28.

The area ratio contributes most of the factor and the lever the rest. Both are geometrical: no energy is added, and the same calculation carried out on the energy gives no gain.

Inside the cochlea

Once through the oval window, the vibration travels in the cochlea's fluid and along the basilar membrane that runs the length of its coil. The membrane is not uniform: it is narrow and stiff near the oval window and becomes wider and floppier towards the far end, so each frequency disturbs its own region of the membrane most, high frequencies peaking near the entrance and low frequencies far along.

The cochlea uncoiled: the basilar membrane is narrow and stiff at the oval window and wide and floppy at the apex, so an 8 kHz tone peaks near the entrance and a 200 Hz tone far along, and the hair cells at each peak are the ones that fire, so position along the membrane codes pitch
Describe the drawing

The cochlea drawn uncoiled as a channel tapering from the oval window at the left to the apex at the right, with the basilar membrane running along it as a wedge, narrow at the window and wide at the apex. Three computed response envelopes sit on the membrane: an 8 kHz tone peaking close to the entrance, a 1 kHz tone near the middle and a 200 Hz tone far along by the apex. A row of hair cells lines the membrane, and at each peak the cell beneath is enlarged with an impulse arrow leaving it for the brain: pitch is read off from which place fired, not from any arithmetic on the wave.

FIG. 3The cochlea uncoiled. The basilar membrane is stiff near the oval window and floppy at the far end, so a high-frequency sound peaks near the entrance and a low-frequency one far along, and the hair cells at the peak are the ones that fire.

Hair cells sit along the membrane, and the ones at the disturbed region are bent by the motion and fire nerve impulses to the brain. Position along the cochlea is therefore how the ear codes pitch: the brain does no frequency arithmetic; it reads an address. A pure tone excites one small stretch of membrane, a chord excites several at once, and the nerve reports which stretches were busy.

That completes the chain the specification asks for, air to bone to fluid to nerve: pinna, canal, eardrum, ossicles, oval window, cochlea, hair cells, brain.

Intensity, and why the scale is logarithmic has moved to the next part of this lesson.

Equal loudness curves has moved to the next part of this lesson.

What damage does to the curves has moved to the next part of this lesson.

ASSESSMENT FOCUS

  • Give the transmission chain in order, with the medium at each stage. Pinna and canal in air, eardrum, three ossicles across the middle ear, oval window, fluid in the cochlea, hair cells, nerve impulses.
  • Give both reasons for the pressure gain. The ossicles act as a lever, and the eardrum's area is far larger than the oval window's, so the same force acts over a much smaller area.
  • Say what the pressure gain is for. The cochlea is fluid-filled, and without the middle ear almost all the sound would reflect at the air-to-fluid boundary instead of entering.
  • The gain is a pressure gain, not an energy gain. Nothing in the middle ear adds energy to the wave, so describe it as pressure transformation rather than as active power amplification.
  • Pitch answers turn on position. Each frequency disturbs its own region of the basilar membrane most, and the brain reads which hair cells fired, so position along the cochlea codes the pitch.

CHECK YOURSELF

The eardrum of a particular ear has an area of 60 mm2 and its oval window an area of 3.2 mm2, and the ossicles multiply the force by 1.3. Calculate the factor by which the pressure is raised across the middle ear, and explain why the increase is necessary.

Show a hint

Pressure is force per area: the lever multiplies the force, and the smaller window divides the area.

Show the answer

The area ratio alone raises the pressure by 60/3.2 = 19 times, because the ossicles deliver the eardrum's force to a much smaller area.

The lever multiplies the force by 1.3 on the way across, so the overall gain is 1.3 × 60/3.2 = 24.

The cochlea beyond the oval window is filled with fluid, and sound arriving from air at a fluid boundary would almost all reflect. The pressure step-up is what drives the vibration into the fluid, so without it almost none of the sound's energy would enter the inner ear.

Sound crosses the ear in order: pinna, canal, eardrum, ossicles, oval window, cochlea, hair cells, nerve, passing from air to bone to fluid.

The middle ear raises the pressure by a lever and an area ratio, so the sound can get into the fluid of the cochlea.

Position along the cochlea codes pitch: each frequency disturbs its own stretch of the basilar membrane most.

WORKBOOK

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  • Describe the transmission of sound through the outer, middle and inner ear.
  • Explain why the middle ear raises the pressure before the sound reaches the cochlea.

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